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First and Second Order Systems - Classical Analysis |
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| Jan29-13, 05:56 AM | #1 |
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First and Second Order Systems - Classical Analysis
This was a lecture example and it has confused me. Can someone please help explain it?
If we have the following fist order system: τ.dx/dy+y(t)=x(t) where τ=c/k where "k" is the spring stiffness and "c" the linear damper coefficient and τ is a time constant. For the unforced case x(t)=0, we need to write down an expression for the response when the initial condition is y(0)=y0. ANd how do we sketch the repsonse? |
| Feb18-13, 07:43 PM | #2 |
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I have to clarify something before giving any advisement.
Are you sure the differential equation is what you have provided or is it: τ.dy/dt + y(t) = x(t) The reason I ask is the above equation represents a first order spring-damper system where τ = (dampening coefficient/spring stiffness), as you stated. |
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