
#1
Feb1413, 04:38 PM

P: 33

Hi, i have problems understanding the Brilluoin zone to the bcc lattice
First, i wonder what the distances are, from the origo to the brillouin zone plane borders. I firts thought it would be half the distance of the basis vectors (mine are 2pi/a, where a is my lattice constant, BUT its only true for 2D calculations for square lattices. I know that the distances in 3D should be Gvector/2, and i take the smallest possible G. But i still dont know ANyone who knows how to find the distances from origo to the first BZ zone boundaries, knowig that the basis vector in the reciprocal space is 2pi/2?are they all the same?? 



#2
Feb1513, 05:56 AM

P: 241

I think if the direct lattice constant is a, then the reciprocal lattice constant would be[itex]2\pi/a[/itex] hence your favorite distance is [itex](\pi/\sqrt2)a[/itex].




#3
Feb1513, 07:52 AM

P: 33

Thanks a lot. and this goes eveforryone of the 12 directions in the BZ?




#4
Feb1513, 04:34 PM

P: 241

Bcc lattice
No, it was for the four direction located in the middle of the figure 4.16 Ashcroft & Mermin. you can easily calculate it for remained 8 directions (see the figure).




#5
Feb1513, 04:45 PM

P: 33

ok thanks. im jut interested in the 110direvtion, from origo to N,in the Ʃdirection



Register to reply 
Related Discussions  
primitive lattice vectors, reciprocal lattice, wigner seitz cell  Atomic, Solid State, Comp. Physics  1  
Lattice QCD  High Energy, Nuclear, Particle Physics  4  
Difference between 1D lattice and 2D lattice on BEC  Atomic, Solid State, Comp. Physics  4  
Onedimensional monatomic chain; square lattice; hcp close packed 2D lattice  Advanced Physics Homework  0  
Does any lattice or lattice shape has a periodic boundary condition?  Classical Physics  4 