Having some trouble differentiating

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SUMMARY

The discussion focuses on differentiating the function y = x^{\sqrt{x}}. The initial derivative expression is correctly identified as x^{\sqrt{x}} \cdot \ln(x) \cdot \frac{1}{2\sqrt{x}}. The user is guided to use logarithmic differentiation, leading to the equation ln(y) = (\sqrt{x})(ln(x)). By differentiating both sides with respect to x and substituting back for y, the complete derivative can be obtained. This method effectively simplifies the differentiation process for functions involving variable exponents.

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I'm having some trouble differentiating [itex]x^{\sqrt x }[/itex]. I know that the derivative of [itex]x^{\sqrt x }[/itex] probably begins with [itex]x^{\sqrt x } \cdot \ln (x) \cdot \frac{1}{{2\sqrt x }}[/itex] but once the base is also x then there is probably more to it than that. Anyone?
 
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You have [tex]y=x^{\sqrt x }[/tex]
So, [tex]\ln y = (\sqrt x)(\ln x)[/tex]
Then differentiate both sides with respect to x and substitute the value of y.
 
Ah, yes, thanks siddharth!
 

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