The tangent slope at the point y=cosh x=1 is equal to 0. This is because the function y=cosh x=1 has a horizontal slope at x=0, meaning that the slope of the curve at this point is 0.
The tangent slope at the point y=cosh x=1 can be calculated using the derivative of the function y=cosh x=1. The derivative of cosh x is sinh x, and when x=0, sinh x=0, hence the slope at this point is 0.
The tangent slope at the point y=cosh x=1 represents the rate of change of the function y=cosh x with respect to x at x=0. It indicates the steepness of the curve at this particular point.
Yes, the tangent slope at the point y=cosh x=1 is constant. This is because the function y=cosh x=1 is symmetric about the y-axis, and therefore, the slope of the curve at x=0 will remain the same for all values of x.
No, the tangent slope at the point y=cosh x=1 can never be negative. This is because the function y=cosh x=1 is always increasing and the slope at x=0 is 0, meaning that the slope will always be positive for all values of x.