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Oster
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I have to prove that every subgroup H of a group G with index(number of distinct cosets of the subgroup) 2 is normal.
I don't know how to start :'(
Please help.
I don't know how to start :'(
Please help.
For a given group, the index of a subgroup is the number of cosets (distinct left or right translates) of the subgroup in the group. If a subgroup has an index of 2, it means that there are exactly two cosets of the subgroup in the group.
A subgroup having an index of 2 indicates that the subgroup is a normal subgroup, which means it is invariant under conjugation by elements of the larger group. This allows for simpler and more efficient computations and can provide insights into the structure of the group.
The statement "every subgroup of index 2 is normal" means that for any group, if a subgroup has an index of 2, then it is guaranteed to be a normal subgroup. In other words, the index of a subgroup is a sufficient condition for it to be normal.
No, a subgroup cannot have an index of 2 and not be normal. This is because the index of a subgroup being 2 is a necessary and sufficient condition for it to be normal. If a subgroup has an index of 2, then it must be normal.
This statement applies to all groups, regardless of their specific structure or properties. It is a fundamental result in group theory that is applicable to any group with subgroups of index 2.