- #1
Chuck37
- 52
- 0
I've been beating my head against this problem for hours. I see numerically that two expressions are equal, but I can't prove it:
(J[itex]^{T}[/itex]R[itex]^{-1}[/itex]J + P[itex]^{-1}[/itex])[itex]^{-1}[/itex]J[itex]^{T}[/itex]R[itex]^{-1}[/itex]
=
PJ[itex]^{T}[/itex](JPJ[itex]^{T}[/itex] + R)[itex]^{-1}[/itex]
J is arbitrary size, P and R are square though not necessarily equal. Can anyone help? I thought binomial inverse theorem would save me but I haven't been able to get rid of the extraneous terms.
(J[itex]^{T}[/itex]R[itex]^{-1}[/itex]J + P[itex]^{-1}[/itex])[itex]^{-1}[/itex]J[itex]^{T}[/itex]R[itex]^{-1}[/itex]
=
PJ[itex]^{T}[/itex](JPJ[itex]^{T}[/itex] + R)[itex]^{-1}[/itex]
J is arbitrary size, P and R are square though not necessarily equal. Can anyone help? I thought binomial inverse theorem would save me but I haven't been able to get rid of the extraneous terms.