- #1
neelakash
- 511
- 1
I want to discuss the answers (what I get and what is given) of the following problem:
A particle slides down a smooth inclined plane of elevation θ,fixed in an elevator going up with an acceleration a.The base of the incline has a length L.Find the time taken by the particle to reach the bottom.
Working from an inertial frame I got the acceleration down the incline as (g-a) sinθ whereas working from elevator frame(non-inertial) one gets the acceleration down the incline as (g+a) sinθ.Why is there a difference?
Normally,when we see an object from outside an elevator and from the elevator,we se that the normal reaction force to be the same.So,what is making the difference?
A particle slides down a smooth inclined plane of elevation θ,fixed in an elevator going up with an acceleration a.The base of the incline has a length L.Find the time taken by the particle to reach the bottom.
Working from an inertial frame I got the acceleration down the incline as (g-a) sinθ whereas working from elevator frame(non-inertial) one gets the acceleration down the incline as (g+a) sinθ.Why is there a difference?
Normally,when we see an object from outside an elevator and from the elevator,we se that the normal reaction force to be the same.So,what is making the difference?