- #1
ziyad
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When we derive the phase difference in the classical experiment of the solenoid as shown below
http://www.public.asu.edu/~ziyads/Aharonovbohm.pdf
Now what if we change the path from the sorce to screen so it follows a rectangular path like this
http://www.public.asu.edu/~ziyads/rect.gif
the phase difference i.e equation 10 in the slides above will remain the same cause no matter what the path the the closed loop integral of the curl of A remains the same.
NOw what if I change it a bit, and apply a parpendicular magnetic field throughout the region and my gauge is A=(-By/2, Bx/2,0)
How will the phase differnce change of the rectangular path.
and what about if A=(By,0,0) which should be the same as that of A=(-By/2, Bx/2,0)
http://www.public.asu.edu/~ziyads/Aharonovbohm.pdf
Now what if we change the path from the sorce to screen so it follows a rectangular path like this
http://www.public.asu.edu/~ziyads/rect.gif
the phase difference i.e equation 10 in the slides above will remain the same cause no matter what the path the the closed loop integral of the curl of A remains the same.
NOw what if I change it a bit, and apply a parpendicular magnetic field throughout the region and my gauge is A=(-By/2, Bx/2,0)
How will the phase differnce change of the rectangular path.
and what about if A=(By,0,0) which should be the same as that of A=(-By/2, Bx/2,0)
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