Tensile force in elevator problem

In summary, two blocks of mass m are hung from the ceiling of an elevator with upward acceleration a. The tensions T1 and T2 are given by T1 = 2(ma + mg) and T2 = ma + mg. The upper string would break first. If the cable supporting the elevator breaks, the elevator and its contents will be in free fall with an acceleration of 0, resulting in T1 = 0 and T2 = 0.
  • #1
bdh2991
103
0

Homework Statement


Two blocks, each of mass m are hung from the ceiling of an elevator as in the figure below. The elevator has an upward acceleration a. The strings have negligible mass.

http://imageshack.us/a/img856/2241/5p031.gif

Find the tensions T1 and T2 in terms of m, a, and g.

Which string would break first if a was sufficient large?

What are the tensions if the cable supporting the elevator breaks?



Homework Equations



F = ma

The Attempt at a Solution



My answers were:

T1 = 2(ma + mg)
T2 = ma + mg

the upper string would break first

T1 = 2(-ma + mg)
T2 = -ma + mg

can anyone please check my work and see if these answers are correct? thanks
 
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  • #2
Looks good for the first part. For the second part, the elevator could no longer be accelerating up, since only gravity firce would be acting down. The elevator and its contents would be in free fall. In free fall, what is the acceleration? Redo your calcs for the tensions.
 
  • #3
PhanthomJay said:
Looks good for the first part. For the second part, the elevator could no longer be accelerating up, since only gravity firce would be acting down. The elevator and its contents would be in free fall. In free fall, what is the acceleration? Redo your calcs for the tensions.

So...if the object is in free fall that would mean:

T1 = 0 and T2 = 0?
 
  • #4
Yes, good.
 
  • #5
Thank you for the help. Makes sense now that i think about it the right way
 

1. What is a tensile force in an elevator problem?

A tensile force in an elevator problem refers to the force that is placed on the elevator cables as the elevator moves up or down. It is the force that is required to lift the weight of the elevator and its passengers.

2. Why is understanding the tensile force in an elevator important?

Understanding the tensile force in an elevator is important because it helps engineers design safe and efficient elevators. By knowing the maximum tensile force that the elevator cables can withstand, engineers can ensure that the elevator can safely carry its maximum load without breaking.

3. How is the tensile force in an elevator calculated?

The tensile force in an elevator can be calculated by multiplying the weight of the elevator and its passengers by the acceleration due to gravity. This will give the total force that the elevator must counteract in order to move upward. This force is then divided by the number of elevator cables to determine the required tensile force for each cable.

4. What factors can affect the tensile force in an elevator?

The main factors that can affect the tensile force in an elevator include the weight of the elevator and its passengers, the acceleration or deceleration of the elevator, and the number and strength of the elevator cables. Other factors such as friction in the pulley system and wind resistance can also play a role in determining the tensile force.

5. How can the tensile force in an elevator be reduced?

The tensile force in an elevator can be reduced by reducing the weight of the elevator and its passengers, decreasing the acceleration or deceleration of the elevator, or increasing the number and strength of the elevator cables. Additionally, using a more efficient pulley system and reducing wind resistance can also help to reduce the tensile force.

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