- #1
mooneh
- 24
- 0
vertical and horizontal asymptotes of the curve of f(x) = (x^2+x-6)/(9-x^2 ) are respectively :
a) x=3,x=-3,y=-1 b)x=3,y=-1 c)x=3,y=1 d)x=-3,y=-1
i did the infinit limit to find the horizontal asymptote and i got -1
then to solve the vertical; 9-x^2 = 0 and so x= √9 so x= 3 and x=-3
but the right answer is b) x=3,y=-1
why ?
a) x=3,x=-3,y=-1 b)x=3,y=-1 c)x=3,y=1 d)x=-3,y=-1
i did the infinit limit to find the horizontal asymptote and i got -1
then to solve the vertical; 9-x^2 = 0 and so x= √9 so x= 3 and x=-3
but the right answer is b) x=3,y=-1
why ?