- #1
ProPatto16
- 326
- 0
a certain bifringement material has indexes of refraction n1 and n2 for the two perpendicular components of linearly polarized light passing through it. the corresponding wavelengths are λ1=λ0/n1 and λ2=λ0/n2, where λ0 is wavelength in vacuum. If crystal is to function as a quarter-wave plate, the number of wavelengths of each component within a material must differ by 1/4. show that the minimum thickness for a quarter-wave plate is
d=λ0/[4(n1-n2)]
i have no idea. i can see all the numbers are there, but i can't see how to actually "show" it.
thanks
d=λ0/[4(n1-n2)]
i have no idea. i can see all the numbers are there, but i can't see how to actually "show" it.
thanks