- #1
braindead101
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question:
three uniform disks of the same mass per unit area, and radii a, 2a, 3a are placed in contact with each other with their centers on a straight line. how far is the center of mass of the system from the center of the smallest disk?
solution:
m1=pi a^2
m2=4pi a^2
m3=9pi a^2
Xc = (m1/mtotal)Xo + (m2/mtotal)(Xo+3a)+(m3/mtotal)(Xo+8a)
Xc = 1/14Xo + 4/14Xo + 6/7a + 9/14Xo + 72/14a
Xc = Xo + 6a
therefore center of mass of system is 6a from the center of the smallest disk.
is this correct?
three uniform disks of the same mass per unit area, and radii a, 2a, 3a are placed in contact with each other with their centers on a straight line. how far is the center of mass of the system from the center of the smallest disk?
solution:
m1=pi a^2
m2=4pi a^2
m3=9pi a^2
Xc = (m1/mtotal)Xo + (m2/mtotal)(Xo+3a)+(m3/mtotal)(Xo+8a)
Xc = 1/14Xo + 4/14Xo + 6/7a + 9/14Xo + 72/14a
Xc = Xo + 6a
therefore center of mass of system is 6a from the center of the smallest disk.
is this correct?