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http://img138.imageshack.us/img138/2042/untitled15mr.jpg
theta = 21 degrees
Mu = 0
radius = 150 meters
a = radial acceleration of uniform circular motion
a = v^2 / r
The sum of all forces = m*a
Since the car is at an angle and Fn is always perpendicular I split it into X and Y components.
Fn in the x direction = Fn sin theta
Fn in the y direction = Fn cos theta
X direction: Fn sin theta = m (v^2 / r)
Y direction: no acceleration so Fn cos theta - Fg = 0
Fn = (mg / cos theta)
By substitution into the equation for the x direction:
( mg / cos theta ) * sin theta = m (v^2 / r)
mg tan theta = m (v^2 / r)
cancelling m and re-arranging...
tan theta = ( v^2 / rg )
v^2 = tan 21 / (150 * 9.8)
v^2 = 564.28
v = 23.75 meters per second
Is this answer correct?
theta = 21 degrees
Mu = 0
radius = 150 meters
a = radial acceleration of uniform circular motion
a = v^2 / r
The sum of all forces = m*a
Since the car is at an angle and Fn is always perpendicular I split it into X and Y components.
Fn in the x direction = Fn sin theta
Fn in the y direction = Fn cos theta
X direction: Fn sin theta = m (v^2 / r)
Y direction: no acceleration so Fn cos theta - Fg = 0
Fn = (mg / cos theta)
By substitution into the equation for the x direction:
( mg / cos theta ) * sin theta = m (v^2 / r)
mg tan theta = m (v^2 / r)
cancelling m and re-arranging...
tan theta = ( v^2 / rg )
v^2 = tan 21 / (150 * 9.8)
v^2 = 564.28
v = 23.75 meters per second
Is this answer correct?
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