Solve Banked Curve Problem: theta=21deg, Mu=0, r=150m

In summary, the conversation discusses the calculation of the radial acceleration of uniform circular motion using the equations a = v^2 / r and sum of all forces = m*a. The conversation also mentions splitting the force into x and y components and adjusting for the angle of the car. The final answer is determined to be 23.75 meters per second.
  • #1
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http://img138.imageshack.us/img138/2042/untitled15mr.jpg

theta = 21 degrees
Mu = 0
radius = 150 meters
a = radial acceleration of uniform circular motion

a = v^2 / r

The sum of all forces = m*a

Since the car is at an angle and Fn is always perpendicular I split it into X and Y components.

Fn in the x direction = Fn sin theta
Fn in the y direction = Fn cos theta

X direction: Fn sin theta = m (v^2 / r)

Y direction: no acceleration so Fn cos theta - Fg = 0
Fn = (mg / cos theta)

By substitution into the equation for the x direction:

( mg / cos theta ) * sin theta = m (v^2 / r)

mg tan theta = m (v^2 / r)

cancelling m and re-arranging...

tan theta = ( v^2 / rg )

v^2 = tan 21 / (150 * 9.8)
v^2 = 564.28

v = 23.75 meters per second


Is this answer correct?
 
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  • #2
Yes.
Your working is pefectly correct and the answer is correct.

There's just a little typo. You used a '/'-sign instead of a '*'-sign between the tan21 and the 150*9.8
 
  • #3
Yes you are correct with the equations tan(theta) = v^2/rg.
 

1. How do you determine the necessary speed for a car to safely navigate a banked curve with a given angle, coefficient of friction, and radius?

To solve this banked curve problem, you can use the formula v = sqrt(rgtan(theta) + rg(mu + gcos(theta))), where v is the necessary speed, r is the radius, theta is the angle of the curve, mu is the coefficient of friction, and g is the acceleration due to gravity.

2. What is the significance of the coefficient of friction in determining the necessary speed for a banked curve?

The coefficient of friction represents the amount of friction between the tires of the car and the surface of the road. It plays a crucial role in determining the necessary speed for a car to safely navigate a banked curve, as a higher coefficient of friction allows for a higher speed.

3. Can a car safely navigate a banked curve if the coefficient of friction is zero?

Yes, a car can still safely navigate a banked curve if the coefficient of friction is zero, as long as the necessary speed is maintained. In this case, the formula v = sqrt(rgtan(theta)) can be used.

4. How does changing the angle of the curve affect the necessary speed for a banked curve?

As the angle of the curve increases, the necessary speed also increases. This is because a steeper banked curve requires a higher centripetal force to keep the car on the track.

5. What happens if the radius of the curve is smaller than the necessary radius calculated for a given speed?

If the radius of the curve is smaller than the necessary radius calculated for a given speed, the car will experience a centrifugal force that may cause it to slide off the track. In this case, the speed must be reduced in order for the car to safely navigate the curve.

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