- #1
jesuslovesu
- 198
- 0
Homework Statement
A coaxial cable has a line charge running through it's center with a line charge density [tex]\lambda[/tex]. There is a dielectric filled between the line charge and the first conducting shell cylinder and another dielectric between the outer cylindrical shell and the inner cylindrical shell.
Homework Equations
[tex]D_{1n} - D_{2n} = \rho_s[/tex]
The Attempt at a Solution
My question is, in the equation to the bottom will rho have a value? Since the line charge is the only thing with direct charge on it, can I ignore the fact that there is a conductor separating the dielectrics?
I know the inner conductor will have a negative charge to counteract the field coming from the line charge, but with that equation isn't it applicable if the surface is directly charged?
so can i just say [tex] D_{1n} = D_{2n} [/tex] in this case anyway?