- #1
Whalstib
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Electrolysis
When calculating amount of charge from an amount of product in an electrolysis the typical equations proceeds for instance:
.404g Cu * (1 mole Cu/63.6g) * (2 moles electrons/1 moles Cu) * (96485/1 mole e) = 1.226 E3 C
BUT when solving for amount of product for instance we go like this:
5.11C *(1 mole e/96485) * ( 1 mole I2/ 2 mole e) * (254 g I2/1 mol I2) = 6.73 E-3 g I2
My question is in regards to the Faraday Number which is highlighted.
Why is the fraction associated with the Faraday Number inverted? Since there are 5 variable to solve for how does one know which one to use?
I have 2 reference books Ebbing’s and Zumdahls textbooks and neither explains this.
Any clues and how I can tell which to use to say solve for time give the other variables?
Thanks,
W
When calculating amount of charge from an amount of product in an electrolysis the typical equations proceeds for instance:
.404g Cu * (1 mole Cu/63.6g) * (2 moles electrons/1 moles Cu) * (96485/1 mole e) = 1.226 E3 C
BUT when solving for amount of product for instance we go like this:
5.11C *(1 mole e/96485) * ( 1 mole I2/ 2 mole e) * (254 g I2/1 mol I2) = 6.73 E-3 g I2
My question is in regards to the Faraday Number which is highlighted.
Why is the fraction associated with the Faraday Number inverted? Since there are 5 variable to solve for how does one know which one to use?
I have 2 reference books Ebbing’s and Zumdahls textbooks and neither explains this.
Any clues and how I can tell which to use to say solve for time give the other variables?
Thanks,
W