Recharge Time Calculation for Run Down Battery | Q1 & Q2 Answer Check

[r-soy]

Hi all

Q1 : when a run down battery is recharged 22600C of charge is required comput the time in hour needed to recharge the battery to 8A current ?

my answer is : t = Q / I = 22600 / 8 = 2825

Q2 : calculate the number of Faraday required depositing 1 X 10^-5moles of cu from cu^2 ?

my answer is
Cu ----- > cu^2+

the charge of cu = 3
the number of Faraday needed to deposit 1 mole will be = 3F
the number of Faraday needed to deposit 1 X 10^-5 mole will be = 3F X 1 X 10^-5
= 3 X 10^-5 F

I want check my solving

thanks

 

[Zefram]

Hi there,

I would like to provide some feedback on your answers to the questions.

For Q1, your calculation for the time needed to recharge the battery to 8A is correct. However, it is important to note that this calculation assumes a constant current and does not take into account any losses during the charging process. In reality, the time needed to recharge a battery may be longer due to factors such as internal resistance and heat dissipation.

For Q2, your calculation for the number of Faraday needed to deposit 1 X 10^-5 moles of Cu from Cu^2+ is also correct. However, it is important to clarify that the charge of Cu is not always 3. It depends on the oxidation state of Cu in the compound. In this case, Cu^2+ has a charge of 2, so the number of Faraday needed would be 2F for 1 mole of Cu. Your calculation for 1 X 10^-5 moles is correct, but it is important to specify the charge of the species in question.

I hope this helps and keep up the good work!