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francisg3
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a congested computer network has a 0.002 probability of losing a data packet and packet losses are independent events. a lost packet must be resent.
a) what is the probability that an e-mail with 100 packets will need any resent?
i know the answer is P= 1-(1-0.002)^100
however i need some help understanding why it is so. i kno the (1-0.002) si the probability that a packet is not lost. i also know that since there are 100 packets in the e-mail, that there are x^100 chances of it not being lost.
i do not understand why (1-0.002)^100 is subtracted from 1, wouldn't this give the probability that ALL are lost?
also, why can't you just do (probability packets lost)^100?, (0.002)^100
a) what is the probability that an e-mail with 100 packets will need any resent?
i know the answer is P= 1-(1-0.002)^100
however i need some help understanding why it is so. i kno the (1-0.002) si the probability that a packet is not lost. i also know that since there are 100 packets in the e-mail, that there are x^100 chances of it not being lost.
i do not understand why (1-0.002)^100 is subtracted from 1, wouldn't this give the probability that ALL are lost?
also, why can't you just do (probability packets lost)^100?, (0.002)^100
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