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maiad
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Homework Statement
In the arrangement shown in the figure below, a potential difference DeltaV is applied, and C1 is adjusted so that the voltmeter between points b and d reads zero.
http://capa.physics.mcmaster.ca/figures/sb/Graph26/sb-pic2667.png
This "balance" occurs when C1 = 3.56 µF. If C3 = 9.50 µF and C4 = 12.3 µF, calculate the value of C2
Homework Equations
CΔV=Q
The Attempt at a Solution
I know that capacitor 1-2, 3-4 is connected in series and the charge on capacitors 1-2, 3-4 are the same because the voltmeter reads zero which mean there's no transfer of electrons between the plates so the charge of the capacitors connected in series should be the same. I came up with the following attempt:
1: C(equivalent 1-2)=(1/C1)+(1/C2)
2:C(equivalent 3-4)=(1/C3)+(1/C4)
3:C(total)= C(equivalent 1-2)+C(equivalent 3-4)
4:Qtotal=Q1+Q2
5:Qtotal= ΔV(C(equivalent 1-2)+C(equivalent 3-4))
When i got step 5, i realized everything just cancels out... lol
so where did I go wrong in my approach?
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