Understanding Wien's Law: Power Radiated & Wavelength

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In summary, the conversation discusses the topics of blackbodies, power radiation, Wien's law, and Planck's law. The speaker asks a question about why the most power is not radiated at the shortest wavelength and the conversation shifts to a discussion about the derivation of Wien's law and its relationship to Planck's work on the quantization of radiation energy. The speaker also mentions the original derivation of Planck's law and provides a reference for further reading. It is noted that Wien's law predates Planck's work but was later supported by his findings.
  • #1
PsychonautQQ
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My physics textbook is talking about blackbodies and has a graph showing Power radiated as a function or wavelength on the y-axis and wavelength on the x axis. The slope grows to it's maximum value exponentially and then decays exponentially. They clarify that the peak of the graph is the wavelength that provides the maximum power radiated, and go on to talk about Wien's law.

My question is why is the most power not radiated at the shortest wavelength? E = hc/λ? Why is it dependent on the temperature?
 
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  • #2
This comes from Planck's Law, i.e., the quantization of the electromagnetic field.

The shortcut derivation from semiclassical arguments, following mostly Planck's original derivation, goes as follows. First you start counting the number of modes in a frequency interval [itex]\mathrm{d} \omega[/itex] of electromagnetic waves. To this end think of a cubic volume [itex]L^3[/itex]. Only waves with wave numbers [itex]\vec{k} \in \pi/L \mathbb{N}^3[/itex] "fit" into the volume. The corresponding modes are given by
[tex]\vec{E} \propto \sin(k_1 x) \sin(k_2 y) \sin(k_3 z),[/tex]
fullfilling the boundary condition that [itex]\vec{E}=0[/itex] at the boundary of the volume. The number of modes in a frequency interval of width [itex]\mathrm{d} \omega[/itex] around [itex]\omega=c k[/itex] thus is
[tex]\mathrm{d} N=\mathrm{d}^3 \vec{k} 2 \frac{L^3}{\pi^3} = \mathrm{d} k k^2 4 \pi 2 \frac{L^3}{(2 \pi)^3}.[/tex]
The factor 2 comes from the two polarization states of the em. waves. In the last step we have written the volume elment in spherical coordinates and integrated out the angles. We have to multiply by [itex]1/8[/itex] because only the octand with positive wave numbers has to be taken. Written in terms of frequency we finally get
[tex]\mathrm{d} N=\mathrm{d} \omega 8 \pi \frac{L^3}{(2 \pi c)^3}.[/tex]
To get the energy spectrum we need the average energy in each mode at given temperature. According to classical physics each mode represents an oscillator, and its mean energy is thus [itex]k T[/itex] according to the equipartition law. This leads, however, to a wrong energy spectrum, particularly a divergent total energy in the electromagnetic field (Rayleigh-Jeans UV catastrophe), and only then your "intuitive" idea that the highest frequencies give the most energy in the radiation field.

Now, according to Planck's and Einstein's hypothesis on the quantization of radiation energy, each oscillator can take only discrete energy levels, [itex]E_n=n \hbar \omega[/itex] with [itex]n \in \mathbb{N}_0[/itex]. That means that the mean energy is
[tex]\frac{\sum_{n=0}^{\infty} n \hbar \omega \exp(-n \hbar \omega/(k T))}{\sum_{n=0}^{\infty} \exp(-n \hbar \omega/(k T))}=\frac{\hbar \omega}{\exp(\hbar \omega/(kT))-1}.[/tex]
The energy spectrum is thus given by
[tex]\mathrm{d} \epsilon=\frac{8 \pi \hbar \omega^3}{(2 \pi c)^3 [\exp(\hbar \omega/(kT))-1]} \mathrm{d} \omega,[/tex]
where [itex]\epsilon=E/V=E/L^3[/itex] denotes the energy density. This can be rewritten in terms of the wavelength, and finding the value for the maximum of the corresponding spectral function leads to Wien's displacement law: The wavelength of maximal emission fulfills the rule
[tex]\lambda_{\text{max}} T=\text{const}.[/tex]
 
  • #3
This comes from Planck's Law, i.e., the quantization of the electromagnetic field.

The shortcut derivation from semiclassical arguments, following mostly Planck's original derivation, goes as follows. First you start counting the number of modes in a frequency interval dω of electromagnetic waves.
Could you give a reference? I do not think what you wrote is Planck's original derivation. This is more like Debye or Drude if I remember correctly. Planck quantized material harmonic oscillators, not EM modes.
 
  • #4
E in E=hc/λ you mentioned, seems to be the energy of a single photon with wavelength λ. What you're dealing with in Wien's law is the energy distribution for whole blackbody radiation - the number of photon is never distributed uniformly over the wavelength in blackbody radiation.

That explains why you cannot apply E=hc/λ to get the wrong Wien's law that would state λmax=0.
 
  • #5
That's true. The derivation I've given, is a pretty hand-waving way using a photon picture (free em. field as a set of harmonic oscillators; I'm not sure who did this first, perhaps Einstein?) Plancks derivation is pretty involved. In a way it's using Bose-Einstein statistics but of course that's not very explicit. I only know the German Annalen article, which can be downloaded for free here:

http://onlinelibrary.wiley.com/doi/10.1002/andp.19013090310/abstract
 
  • #6

1. What is Wien's Law?

Wien's Law is a physical law that describes the relationship between the wavelength of radiation emitted by a blackbody and its temperature. It states that as the temperature increases, the peak wavelength of radiation emitted shifts to shorter wavelengths.

2. How is Wien's Law used in science?

Wien's Law is used in various fields of science, such as astronomy, astrophysics, and thermodynamics. It is used to calculate the temperature of stars and other celestial objects based on the peak wavelength of their emitted radiation. It is also used to study the thermal radiation emitted by objects in different temperature ranges.

3. What is the power radiated by an object?

The power radiated by an object is the amount of energy emitted per unit time. It is a measure of the rate at which an object is emitting radiation and is typically measured in watts (W).

4. How does the power radiated by an object change with temperature?

According to Wien's Law, the power radiated by an object increases with temperature, as the peak wavelength of radiation emitted shifts to shorter wavelengths. This means that as the temperature of an object increases, it emits more radiation and at shorter wavelengths.

5. Is Wien's Law applicable to all objects?

Wien's Law is applicable to all objects that emit thermal radiation, also known as blackbodies. However, it is an idealized law and may not accurately describe the emission of radiation from real-world objects, which may have different properties and behaviors than a perfect blackbody.

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