Vectors- gradient and normal unit vector- is this correct?

In summary, displacement vectors and gradient vectors are two different types of vectors used in the study of covariant and contravariant vectors and derivatives. Displacement vectors are used as the basis for contravariant vectors, while gradient vectors are used as the basis for covariant vectors. The main difference between the two is that displacement vectors represent a change in position or location, while gradient vectors represent a change in a scalar quantity such as temperature or pressure.
  • #1
tomanator
10
0

Homework Statement



For the scalar field f(x, y, z) = x2 − y2 − z find gradf and normal unit
vector to a surface f(x, y, z) = 0 at the point (1, 1, 0).

Homework Equations




The Attempt at a Solution



I calculated gradf= 2xi -2yj -k

at (1,1,0) this is = 2i -2y -k

normal unit vector= [tex]\frac{2i -2y -k}{\sqrt{9}}[/tex]

normal unit vector = [tex]\frac{1}{3}[/tex](2i -2y -k)

is this correct it seems too simple in terms of marks
 
Physics news on Phys.org
  • #2
I think you've calculated the gradient correctly, but not the normal unit vector. The gradient is tangent to the surface in the direction where the slope is maximum. The normal vector is perpendicular to the tangent plane of the surface. So the normal unit vector will be perpendicular to the gradient vector. You have just calculated the unit gradient vector.
 
  • #3
phyzguy said:
I think you've calculated the gradient correctly, but not the normal unit vector. The gradient is tangent to the surface in the direction where the slope is maximum. The normal vector is perpendicular to the tangent plane of the surface. So the normal unit vector will be perpendicular to the gradient vector. You have just calculated the unit gradient vector.

Thanks for you reply, so do you know how I calculate the normal unit vector then?
 
  • #4
Tomanator,
your solution is correct. The gradient in a point of a f(x,y,z)=constant surface is normal to the tangent plane of this surface at the given point.

A small change of f can be written as dF=grad f˙dr, the dot product of the gradf vector with the displacement vector dr. You get the highest change of f if the displacement is parallel to the gradient: the gradient vector points in the direction of the steepest slope of the f function.
If dr is tangent to an f(x,y,z) = constant surface dF=grad f˙dr=0. A dot product of two non-zero vector is 0 if they are perpendicular: gradf and dr are perpendicular, gradf is normal vector to the tangent plane.

ehild
 
  • #5
ehild said:
Tomanator,
your solution is correct. The gradient in a point of a f(x,y,z)=constant surface is normal to the tangent plane of this surface at the given point.

A small change of f can be written as dF=grad f˙dr, the dot product of the gradf vector with the displacement vector dr. You get the highest change of f if the displacement is parallel to the gradient: the gradient vector points in the direction of the steepest slope of the f function.
If dr is tangent to an f(x,y,z) = constant surface dF=grad f˙dr=0. A dot product of two non-zero vector is 0 if they are perpendicular: gradf and dr are perpendicular, gradf is normal vector to the tangent plane.

ehild

Ok thanks ehild, I'm glad I did it correct first time. I have an exam next week so it's promising :)
 
  • #6
but what if dr is not the tangent to the surface ?? how do u calculate the unit normal vector then ?
 
  • #7
The gradient vector is normal to the surfaces f(x,y,z)=constant, and it can be determined from the partial derivatives of f(x,y,z). You do not need any dr to determine it. What I explained was that the gradient vector is really normal to the f=constant surfaces. And you get the change df of the function f when moving from r to r+dr by calculating the dot product grad(f )˙dr=df.

ehild
 
  • #8
yes, i get it .. i always keep forgetting dr is the tangent to the plane of surface. thanks ehild. could you help with what a unit normal vector is ?? is it the direction of the gradient vector? if so, how do you calculate it given the gradient and a point on the surface ?
 
  • #9
tomanator said:

Homework Statement



For the scalar field f(x, y, z) = x2 − y2 − z find gradf and normal unit
vector to a surface f(x, y, z) = 0 at the point (1, 1, 0).

Homework Equations




The Attempt at a Solution



I calculated gradf= 2xi -2yj -k

at (1,1,0) this is = 2i -2y -k

normal unit vector= [tex]\frac{2i -2y -k}{\sqrt{9}}[/tex]

normal unit vector = [tex]\frac{1}{3}[/tex](2i -2y -k)

is this correct it seems too simple in terms of marks

Your calculations are correct: grad f is the direction of steepest ascent (i.e., the direction of greatest rate of increase in f), and grad(f)/|grad(f)| is the corresponding unit normal.

RGV
 
  • #10
msslowlearner said:
yes, i get it .. i always keep forgetting dr is the tangent to the plane of surface. thanks ehild. could you help with what a unit normal vector is ?? is it the direction of the gradient vector? if so, how do you calculate it given the gradient and a point on the surface ?

See the original post.


ehild
 
  • #11
Ray Vickson said:
Your calculations are correct: grad f is the direction of steepest ascent (i.e., the direction of greatest rate of increase in f), and grad(f)/|grad(f)| is the corresponding unit normal.

RGV

Hi RGV,
It was not "tomanator"who asked about finding the normal vector now, but "msslowlearner". "tomanator" solved the problem in the OP, but "msslowlearner" did not look at his solution in the post more than one year ago.

ehild
 
  • #12
yes.., I'm new to the physicsforums .. hardly a week here .. :)
 
  • #13
Hi

I am trying to learn about covariant and contravariant vectors and derivatives. The videos I have been watching talk about displacement vector as the basis for contravariant vectors and gradient as the basis for covariant vectors. Can somone tlel me the difference between displacemement and gradient vectors?
 

1. What is a vector?

A vector is a mathematical quantity that has both magnitude and direction. It is often represented as an arrow in a coordinate system.

2. What is a gradient vector?

A gradient vector is a vector that points in the direction of the steepest increase of a function at a specific point. It is perpendicular to the level curves of the function.

3. How is a gradient vector calculated?

A gradient vector is calculated by taking the partial derivatives of a function with respect to each variable and combining them into a vector. The resulting vector represents the direction and magnitude of the steepest increase of the function.

4. What is a normal unit vector?

A normal unit vector is a vector that is perpendicular to a surface at a specific point and has a magnitude of 1. It is often used in physics and engineering to represent forces or directions of motion.

5. Is it correct to use a normal unit vector to represent a force?

Yes, it is correct to use a normal unit vector to represent a force. In physics, forces are often represented by vectors, and the normal unit vector is a commonly used vector to represent forces that are perpendicular to a surface. However, it is important to ensure that the direction and magnitude of the vector accurately represent the force being applied.

Similar threads

  • Introductory Physics Homework Help
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
12
Views
202
  • Calculus and Beyond Homework Help
Replies
8
Views
876
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Differential Equations
Replies
7
Views
207
Replies
7
Views
795
Back
Top