- #1
hholzer
- 37
- 0
Theorem:
If P(A) = 1, P(B) = 1, then P(AB) = 1
My book starts out with the proof as follows:
P(A U B) >= P(A) = 1, so P(A U B) = 1
How do they reach such a conclusion?
Things I know:
P(A U B) = P(A) + P(B) - P(AB)
How can I use that to be sure that P(A U B) = 1?
If P(A) = 1, P(B) = 1, then P(AB) = 1
My book starts out with the proof as follows:
P(A U B) >= P(A) = 1, so P(A U B) = 1
How do they reach such a conclusion?
Things I know:
P(A U B) = P(A) + P(B) - P(AB)
How can I use that to be sure that P(A U B) = 1?