- #1
preet
- 98
- 0
What do you in these cases:
A function is g(x) = 2 (x-3) ^2 + 4
Find the range when 0 <= x <= 6
steps i took:
0 <= x <=6
0-3 <= x-3 <= 6-3
-3^2 <= (x-3)^2 <= 3^2
9 <= (x-3)^2 <= 9
22 <= 2 (x-3)^2 + 4 <=22
:: what did i do wrong?
correct answer is:
{ y | 4 <= y <= 22 }
---------------------
case#2
A certain function is defined as f(x)=x^2 + 3
if -3 <= x <=3, determine the range
i got {y | 3 <= y <= 9 }
correct answer is:
{y | 3 <= y <= 12}
Thanks in advance
Preet
A function is g(x) = 2 (x-3) ^2 + 4
Find the range when 0 <= x <= 6
steps i took:
0 <= x <=6
0-3 <= x-3 <= 6-3
-3^2 <= (x-3)^2 <= 3^2
9 <= (x-3)^2 <= 9
22 <= 2 (x-3)^2 + 4 <=22
:: what did i do wrong?
correct answer is:
{ y | 4 <= y <= 22 }
---------------------
case#2
A certain function is defined as f(x)=x^2 + 3
if -3 <= x <=3, determine the range
i got {y | 3 <= y <= 9 }
correct answer is:
{y | 3 <= y <= 12}
Thanks in advance
Preet