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LovePhys
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Homework Statement
Determine the longest wavelength of light emitted from this atom.
Homework Equations
[itex]\lambda=\frac{hc}{E}[/itex]
The Attempt at a Solution
I calculated the lowest energy of the light emitted: [itex]E_{min}=2.1(eV)[/itex]
Then the longest wavelength would be: [itex]\lambda_{max}=\frac{hc}{E_{min}}=\frac{4.14×10^{-15}×3×10^{8}}{2.1}≈5.91×10^{-7}(m)[/itex]
What confused me is the energy difference between the ionization level and n=4 is even smaller than 2.1 eV: [itex]1.6-0=1.6(eV)[/itex]. Am I going to take this energy difference as the minimum energy emitted? Also, can you please point out if the way I take the absolute value of the energy levels and subtract them is correct?
Thank you very much.
LovePhys