- #1
Morphayne
- 13
- 0
Hi. I'm confused about calculating the limit of a function involving Euler's number. I need to know the proper way to find the limit so I can determine the equation of the horizontal asymptote of the function. I do know, in my head what the graph looks like so I know that there is a horizontal asymptote is y=0. I just have to show my work, that's where I'm stuck.
Here is the problem:
lim(x->infinity)(2e^x)
My attempt:
lim(x->infinity)(2e^x) = lim(x->infinity)(2/e^-x)
=lim(x->infinity)(2/e^-infinity)
=lim(x->infinity)(2/0)
=0 Therefore: y=0
I'm not sure if I'm doing the problem the right way. If I did somehow get it right, can someone please give me a brief description on the proper method?
Thanks In Advance.
Here is the problem:
lim(x->infinity)(2e^x)
My attempt:
lim(x->infinity)(2e^x) = lim(x->infinity)(2/e^-x)
=lim(x->infinity)(2/e^-infinity)
=lim(x->infinity)(2/0)
=0 Therefore: y=0
I'm not sure if I'm doing the problem the right way. If I did somehow get it right, can someone please give me a brief description on the proper method?
Thanks In Advance.