- #1
luna02525
- 13
- 0
Homework Statement
Assume an elastic collision (ignoring friction and rotational motion).
A queue ball initially moving at 2.2 m/s strikes a stationary eight ball of the same size and mass. After the collision, the queue ball's final speed is 0.61 m/s.
Find the queue ball's angle [tex]\theta[/tex] with respect to its original line of motion. Answer in units of degrees.
Homework Equations
[tex]\frac{1}{2}mv_1_i^2+\frac{1}{2}mv_2_i^2=\frac{1}{2}mv_1_f^2+\frac{1}{2}mv_2_f^2[/tex]
The Attempt at a Solution
[tex]\frac{1}{2}mv_1_i^2+\frac{1}{2}mv_2_i^2=\frac{1}{2}mv_1_f^2+\frac{1}{2}mv_2_f^2[/tex]
[tex]v_1_i^2+v_2_i^2=v_1_f^2+v_2_f^2[/tex]
[tex]v_2_f=2.114 m/s[/tex]
From here I am unsure of how to come to the angle [tex]\theta[/tex] the question is asking for.
I thought it might be:
[tex]tan\theta=\frac{v_2_f}{v_1_i}[/tex]
This is incorrect, though.
Any guidance would be appreciated!
Last edited: