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Antiphon said:There are at least three mathematically distinct approaches to solving this. What technique are you supposed to use?
Thanks. I got it. It's so simple, if C1g is ignored.gneill said:If V1 is an ideal source, then C1g is irrelevant (except for the added current it will draw from the voltage source, it won't have any effect on the voltage delivered to the remainder of the circuit).
Why not remove the load resistor and determine the Thevenin equivalent of the rest? When you then add back the load you'll have a voltage supply and RC voltage divider to analyze (note that the Thevenin voltage will be frequency dependent unless V1 has a given fixed frequency).
An RC circuit is a circuit that contains both a resistor (R) and a capacitor (C). These components work together to store and release electrical energy, creating a time-varying voltage.
The voltage in an RC circuit can be found using the formula V = V0(1 - e-t/RC), where V0 is the initial voltage, t is the time, R is the resistance, and C is the capacitance. This formula is derived from the charge-discharge equation for a capacitor.
The time constant in an RC circuit is the product of the resistance and capacitance (RC). It represents the time it takes for the voltage in the circuit to rise or fall to approximately 63.2% of its initial value.
RC circuits are commonly used in electronic devices such as filters, oscillators, and timing circuits. They are also used in audio equipment, power supplies, and communication systems.
To analyze an RC circuit using Kirchhoff's laws, you can apply Kirchhoff's voltage law (KVL) and Kirchhoff's current law (KCL) to the different loops and junctions in the circuit. This will allow you to set up a system of equations that can be solved to find the voltage and current at different points in the circuit.