- #1
EG78362
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Homework Statement
Given: The surface is frictionless, two blocks in contact with each other move to the right across a horizontal surface.
Note: one block is 2.1kg with a 58N force applied to it, and the other block is 5.7kg with a 13N force applied to it.
Homework Equations
Determine the magnitude of the force exerted on the block with mass 2.1kg by the block with mass 5.7 kg
The Attempt at a Solution
First I subtracted 58N-13N=45 to get the net force, then I divided the net force by the mass of both blocks [45N/7.8kg]=5.769m/s^2 to get acceleration.
Then I multiplied the acceleration by the 2.1kg block to get 12.115N, but this was not the right answer. So thinking that I maybe did it wrong I multiplied the acceleration by the 5.7kg block (32.884N)and this was also incorrect, finally not knowing what I was doing wrong still, I subtracted 32.884-12.115 and of course this was wrong as well. I can't figure out what I'm missing here. Any help would be appreciated.