Vector problem, magnitude of the force

In summary, the conversation discusses determining the magnitude and components of a force P directed along line CB. The horizontal component is given as 1237 N and can be found using the SOH-CAH-TOA formula. The conversation includes a drawing of a right triangle with P as the hypotenuse and the horizontal and vertical components labeled as Px and Py. The correct solution is found and the conversation ends with a thank you for the help.
  • #1
sHatDowN
52
7
Homework Statement
vector problem
Relevant Equations
Vector
Member CB of the vise shown exerts on block B a force P directed along line CB. Knowing that P must have a (1237) N horizontal component, determine (a) the magnitude of the force P, (b) its vertical component

1677425614750.png


i don't get it what the "N horizontal component"
 
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  • #2
N is Newtons.
 
  • #3
Frabjous said:
N is Newtons.
horizontal component
i mean this one
 
  • #4
Draw force P in the drawing then find its horizontal component.
 
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  • #5
kuruman said:
Draw force P in the drawing then find its horizontal component.
exactly that's my problem what the P force
 
  • #6
sHatDowN said:
horizontal component
i mean this one
The horizntal component is given as 1237 N. "N" is the unit for force in SI, newton.
 
  • #7
sHatDowN said:
exactly that's my problem what the P force
sHatDowN said:
a force P directed along line CB.
Can you draw this?
 
  • #8
kuruman said:
Can you draw this?
1677428979875.png

is it correct?
 
  • #9
Do you know how to find the horizontal component of P?
 
  • #10
Frabjous said:
Do you know how to find the horizontal component of P?
No
 
  • #11
sHatDowN said:
No
Can you draw a right triangle with P as the hypotenuse where the other two sides are vertical (label this one Py) and horizontal (label this one Px)?
 
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  • #12
jbriggs444 said:
Can you draw a right triangle with P as the hypotenuse where the other two sides are vertical (label this one Py) and horizontal (label this one Px)?
1677434290537.png
 
  • #13
View attachment 322903
Can you label the hypotenuse as P?

What are the three angles for this triangle? Can you fill in those measures on the drawing?

If you wanted to know the length of ##P_x## and you knew the length of the hypotenuse ##P##, can you think of a useful formula?
 
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  • #14
jbriggs444 said:
If you wanted to know the length of ##P_x## and you knew the length of the hypotenuse ##P##, can you think of a useful formula?
1677436514733.png
 
  • #16
kuruman said:
Try SOH-CAH-TOA.
Sorry sir but we don't have any length of p-x or p-y.
 
  • #17
I find p-x=1013.29 and p-y=709.51
is it correct?
 
  • #18
The given value of 1237 N is one of ##P_x##, ##P_y## or ##P##. Which one do you think it is?
 
  • #19
kuruman said:
The given value of 1237 N is one of ##P_x##, ##P_y## or ##P##. Which one do you think it is?
Yes sorry sir i find out please check .
 
  • #20
sHatDowN said:
Yes sorry sir i find out please check .
I don't understand what you mean by this. Please post a drawing of the triangle like you have in post #14 with the label 1237 N next to the side that you think corresponds to it.
 
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  • #21
kuruman said:
I don't understand what you mean by this. Please post a drawing of the triangle like you have in post #14 with the label 1237 N next to the side that you think corresponds to it.
1677438322371.png
 
  • #22
sHatDowN said:
Knowing that P must have a (1237) N horizontal component,
Is what you have labeled with 1237 N the horizontal component of P?
 
  • #23
kuruman said:
Is what you have labeled with 1237 N the horizontal component of P?
Yes i think.
 
  • #24
Below is a picture of the horizon. Which line do you think best describes the horizontal direction?

(A) From left to right.
(B) From top to bottom.
(C) From top left corner to bottom right corner.

Horizon.jpeg
 
  • #25
kuruman said:
Below is a picture of the horizon. Which line do you think best describes the horizontal direction?

(A) From left to right.
(B) From top to bottom.
(C) From top left corner to bottom right corner.

View attachment 322907
obviously A
 
  • #26
sHatDowN said:
obviously A
Obviously. Now look at my question in post #22 and your answer in post #23.
 
  • #27
kuruman said:
Obviously. Now look at my question in post #22 and your answer in post #23.
Yes Sir Sorry,I was on mistake.
 
  • #28
sHatDowN said:
Yes Sir Sorry,I was on mistake.
OK, then fix your mistake and post the correct solution.
 
  • #29
1677439743969.png

kuruman said:
OK, then fix your mistake and post the correct solution.
 
  • #30
That looks correct.
 
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  • #31
then we solved sample problem.
Thanks for your help.
 

1. What is a vector problem?

A vector problem is a mathematical problem that involves the use of vectors, which are quantities that have both magnitude and direction. These problems often require the use of vector operations such as addition, subtraction, and multiplication.

2. How do you calculate the magnitude of a force?

The magnitude of a force can be calculated using the formula F = ma, where F is the force, m is the mass of the object, and a is the acceleration. It can also be calculated using the Pythagorean theorem, where the magnitude is equal to the square root of the sum of the squares of the x and y components of the force.

3. What units are used to measure the magnitude of a force?

The magnitude of a force is typically measured in units of Newtons (N) in the SI system. In the imperial system, it is measured in pounds (lbs).

4. Can the magnitude of a force be negative?

Yes, the magnitude of a force can be negative. This indicates that the force is acting in the opposite direction of the chosen coordinate system. However, when calculating the magnitude of a force, the negative sign is ignored and only the absolute value is considered.

5. How does the magnitude of a force affect an object's motion?

The magnitude of a force is directly proportional to an object's acceleration, according to Newton's second law of motion (F = ma). This means that a larger force will result in a greater acceleration and therefore a greater change in an object's motion.

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