- #1
Kajayacht
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1. If the accelerating plates are 1.2cm apart and have a potential difference of 25,000V what is the magnitude of the electric field between them?
2. E=V/D
3. E=25,000V/1.2x10^-2m= 2083333.3 V/M
2. E=V/D
3. E=25,000V/1.2x10^-2m= 2083333.3 V/M