Net Force of a Model Rocket in Free Fall

In summary, a model rocket with a mass of 0.50 kg is fired vertically from the ground with a constant net force of 2.0 N acting in a vertical direction. After 6.0 s, its fuel is exhausted and it continues moving as a particle-like object in free-fall, traveling upward, turning around, and falling back down. When it continues upward as a free fall particle, the net force on the rocket is 0 N. As it turns around, the net force remains 0 N. When it is traveling back toward the ground, the net force is still 0 N. Once the fuel stops, the forces acting on the rocket do not change.
  • #1
wicked_vixen
4
0
A model rocket with a mass of 0.50 kg is fired vertically from the ground. Assume that it is streamlined enough that air resistance can be ignored. Suppose it ascends under the influence of a constant net force of 2.0 N acting in a vertical direction and travels for 6.0 s before its fuel is exhausted. Then it keeps moving as a particle-like object in free-fall as it continues upward, turns around, and falls back down.

What is the net force on the rocket when it continues upward as a free fall particle? as it turns around? When it is traveling back toward the ground?
 
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  • #2
Welcome to PF!

Hi wicked_vixen! Welcome to PF! :smile:
wicked_vixen said:
… before its fuel is exhausted. Then it keeps moving as a particle-like object in free-fall as it continues upward, turns around, and falls back down.

What is the net force on the rocket when it continues upward as a free fall particle? as it turns around? When it is traveling back toward the ground?


What do you think?

What forces are acting on the rocket once the fuel stops?

Do they change, and if so, how? :smile:
 
  • #3


The net force on the model rocket when it continues upward as a free fall particle is zero. This is because in free fall, the only force acting on the rocket is the force of gravity, which is balanced out by the rocket's inertia.

When the rocket turns around, the net force on it is still zero. However, the direction of the net force changes from upward to downward as the rocket starts to fall back toward the ground.

When the rocket is traveling back toward the ground, the net force on it is now the force of gravity, which is equal to the rocket's weight. This is because the rocket is no longer expelling fuel and is now subject to the force of gravity pulling it toward the ground.
 

1. What is the net force of a model rocket in free fall?

The net force of a model rocket in free fall is the sum of all the forces acting on the rocket as it falls. This includes the force of gravity pulling the rocket towards the ground, as well as any air resistance or wind that may affect the motion of the rocket.

2. How is the net force of a model rocket in free fall calculated?

The net force of a model rocket in free fall can be calculated using Newton's second law of motion, which states that force is equal to mass times acceleration (F=ma). The mass of the rocket and the acceleration due to gravity (9.8 m/s^2) can be used to determine the net force acting on the rocket.

3. Does the net force of a model rocket in free fall change during its descent?

Yes, the net force of a model rocket in free fall may change during its descent. As the rocket falls, the force of gravity remains constant, but air resistance may increase or decrease depending on factors such as the shape and size of the rocket, as well as the density of the air it is falling through.

4. How does the mass of a model rocket affect its net force in free fall?

The mass of a model rocket does not directly affect its net force in free fall. However, a heavier rocket will experience a greater force of gravity, which will in turn affect its acceleration and therefore its net force. In general, a heavier rocket will experience a greater net force and fall faster than a lighter rocket.

5. Can the net force of a model rocket in free fall be negative?

Yes, the net force of a model rocket in free fall can be negative. This would occur if the force of air resistance is greater than the force of gravity pulling the rocket downwards. In this case, the rocket would experience a deceleration and its net force would be directed upwards.

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