- #1
r16
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In quantum mechanics, why does the Fourier transform
[tex] f(x) = \int_{-\infty}^\infty F(k) e^{ikx}dk [/tex]
represent position and
[tex]F(k) = \int_{-\infty}^\infty f(x) e^{-ikx} dx [/tex]
represent momentum?
[tex] f(x) = \int_{-\infty}^\infty F(k) e^{ikx}dk [/tex]
represent position and
[tex]F(k) = \int_{-\infty}^\infty f(x) e^{-ikx} dx [/tex]
represent momentum?