Valve, Gas fluid flow question

[robin72]

Hi all,
I am new here and need your help.
After sudden opening of a ball valve with cross section area of 10 mm come to an blow up (explosion) of the 2" pipe.
(before opening) Up stream the valve was the gas pressure 190 bar during downstream the pressure was 0 bar, however it was air inside (s.attached).

Downstream of the valve the distance to the orifice plate is 1,5 m, there was upstream the OR an blow up of the pipe about 50%.
Could you explain me the physical phenomenon, mathematical equation would be appreciated.
best regards
robin

 

[Navin A S]

The phenomenon that likely caused the explosion of the pipe is known as water hammer. Water hammer occurs when a valve or faucet is suddenly opened and closed, allowing a sudden surge of high pressure water to enter the system. In this case, the sudden opening of the ball valve allowed a large amount of pressurized air (190 bar) to enter the system, leading to an increase in pressure downstream. This pressure increase was so great that it caused the pipe to rupture. The mathematical equation for calculating the pressure increase caused by water hammer is given by: P = ∆V2/(2gL), where P is the pressure increase, ∆V is the change in velocity of the fluid, g is the acceleration due to gravity and L is the length of the pipe.