- #1
DB
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really isn't calculus but that's the name of my class so, anyway I am having a problem here. i think its pretty simple I am just missing something. I am supposed to find the slope of the tangent line using one point and:
slope of tangent line =
[tex]\frac{f(a+h)-f(a)}{h}[/tex]
[tex]h\rightarrow0[/tex]
find slope of tangent line:
[tex]f(x)=\frac{1}{x}[/tex]
at a=2
so,
[tex]\frac{1}{2+h}-\frac{1}{2}*\frac{1}{h}[/tex]
common denominator X by (1+h)
[tex]\frac{1}{2+h}-\frac{1+h}{2+h}*\frac{1}{h}[/tex]
[tex]\frac{1-1-h}{2+h}*\frac{1}{h}[/tex]
[tex]\frac{-2-h}{2+h}*\frac{1}{h}[/tex]
[tex]\frac{-1(2+h)}{2+h}*\frac{1}{h}[/tex]
[tex]\frac{-1}{h}[/tex]
make "h" zero and I am stuck...
slope of tangent line =
[tex]\frac{f(a+h)-f(a)}{h}[/tex]
[tex]h\rightarrow0[/tex]
find slope of tangent line:
[tex]f(x)=\frac{1}{x}[/tex]
at a=2
so,
[tex]\frac{1}{2+h}-\frac{1}{2}*\frac{1}{h}[/tex]
common denominator X by (1+h)
[tex]\frac{1}{2+h}-\frac{1+h}{2+h}*\frac{1}{h}[/tex]
[tex]\frac{1-1-h}{2+h}*\frac{1}{h}[/tex]
[tex]\frac{-2-h}{2+h}*\frac{1}{h}[/tex]
[tex]\frac{-1(2+h)}{2+h}*\frac{1}{h}[/tex]
[tex]\frac{-1}{h}[/tex]
make "h" zero and I am stuck...