- #1
Mr Virtual
- 218
- 4
Hi all
The question I am going to ask is such that, had I asked it from my friends, they would have laughed at me. Instead I am asking you (atleast I won't have to see you laughing, whether you reply or not ).
We all learned in junior classes that work done in lifting an object of mass m against gravity, to a height h = mgh
In higher standards, we learned that opposite forces cancel each other.
Accordingly, if you have to lift an object of 80 N weight (mg =80 N) upto 1m height (h), you will have to apply a force of 80 N, thus doing 80 J work (=mgh).
But the thing I do not understand is, if 80 N applied by me is canceled by
80 N weight of the object, how is it going to move. And if it is not going to move, how can we do 80 J work.
Where am I wrong? I know textbooks cannot be wrong. But where am I missing it?
So keep laughing, but do answer my question if it is worth it (or even if it is not !).
Thanks
Mr V
The question I am going to ask is such that, had I asked it from my friends, they would have laughed at me. Instead I am asking you (atleast I won't have to see you laughing, whether you reply or not ).
We all learned in junior classes that work done in lifting an object of mass m against gravity, to a height h = mgh
In higher standards, we learned that opposite forces cancel each other.
Accordingly, if you have to lift an object of 80 N weight (mg =80 N) upto 1m height (h), you will have to apply a force of 80 N, thus doing 80 J work (=mgh).
But the thing I do not understand is, if 80 N applied by me is canceled by
80 N weight of the object, how is it going to move. And if it is not going to move, how can we do 80 J work.
Where am I wrong? I know textbooks cannot be wrong. But where am I missing it?
So keep laughing, but do answer my question if it is worth it (or even if it is not !).
Thanks
Mr V