- #1
Deadstar
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Let A,B,C be three cardinals. Show that...
[tex]A^{B+C} = A^B A^C[/tex]
I thought about using some some of distinguishing scheme where we denoted [tex]B \cup C[/tex] as [tex]B \times \{0\} \cup C \times \{1\}[/tex] so we could map thing easily but apparently that's not right and you can assume they are disjoint anyway...
EDIT: I just noticed the sticky at the top, this was just something in the notes we had that wasn't proven, not an assignment question or anything and I wanted to know how to do it. Should I repost this in another section?
[tex]A^{B+C} = A^B A^C[/tex]
I thought about using some some of distinguishing scheme where we denoted [tex]B \cup C[/tex] as [tex]B \times \{0\} \cup C \times \{1\}[/tex] so we could map thing easily but apparently that's not right and you can assume they are disjoint anyway...
EDIT: I just noticed the sticky at the top, this was just something in the notes we had that wasn't proven, not an assignment question or anything and I wanted to know how to do it. Should I repost this in another section?