- #1
transgalactic
- 1,395
- 0
[tex]
f(x)=\frac{1}{1+ln|x|}
[/tex]
the ln|x| part could be -1 when x=e^-1
correct??
f(x)=\frac{1}{1+ln|x|}
[/tex]
the ln|x| part could be -1 when x=e^-1
correct??
transgalactic said:[tex]
f(x)=\frac{1}{1+ln|x|}
[/tex]
the ln|x| part could be -1 when x=e^-1
correct??
A denominator is the bottom number in a fraction that represents the total number of equal parts into which the whole has been divided.
A 0 denominator occurs when the fraction has been divided by 0, which is undefined in mathematics. This is because division by 0 results in an infinite value, which cannot be represented as a number.
There are a few different scenarios where we might get a 0 denominator. One common case is when we are dividing a number by 0, either intentionally or unintentionally. Another case is when we are solving equations and a variable cancels out, resulting in a 0 denominator.
When we have a 0 denominator, the fraction becomes undefined. This means that there is no solution or answer to the problem. In some cases, we may be able to use limits or other techniques to find an approximation, but there is no exact solution.
To avoid getting a 0 denominator, we should always check our work and equations for any potential division by 0. We should also be aware of any variables or numbers that could potentially result in a 0 denominator and make adjustments to our equations accordingly.