- #1
K.J.Healey
- 626
- 0
If I had was given a yukawa potential of the form:
[tex]\text{YL}[\text{r$\_$}]=\left(\left.g_L{}^{\wedge}2\right/r\right) \text{Exp}\left[-\mu _Lr (c/\hbar )\right][/tex]
I put the c/h in the exponent to make it unitless, but what do I do about the outside?
i'm given the coupling constant is 0.3. Just 0.3. So should the potential need the units of eV?
So should i then take what I have and multiply it by "c hbar"? Its an inverse length right now, so i figure "ch" = "m eV s/s"
is this right?
[tex]\text{YL}[\text{r$\_$}]=\left(\left.g_L{}^{\wedge}2\right/r\right) \text{Exp}\left[-\mu _Lr (c/\hbar )\right][/tex]
I put the c/h in the exponent to make it unitless, but what do I do about the outside?
i'm given the coupling constant is 0.3. Just 0.3. So should the potential need the units of eV?
So should i then take what I have and multiply it by "c hbar"? Its an inverse length right now, so i figure "ch" = "m eV s/s"
is this right?
Last edited: