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mottov2
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Homework Statement
Fidn the Fourier expansion for f of period 2Pi that corresponds to y=x/3 on the interval [0,2Pi)
Im just a little confused about if I am setting up the integration properly. The asymmetric interval is kind of confusing me here.
The Attempt at a Solution
a0 = 1/Pi ∫ x/3 dx = 0 (since f is odd) for 0 < x < 2Pi.
ak = 1/Pi ∫ x/3 Cos(kx) dx = 0 (since f is odd) for 0< x < 2Pi
bk = 1/Pi ∫ x/3 Sin(kx) dx for 0 < x < 2Pi
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