Struggling with Unit Conversions in Physics Problems?

In summary, the conversation discusses the correct way to solve a problem involving pressure at a depth of 5 meters in alcohol. It emphasizes the importance of properly converting between units and provides a link for further practice and clarification.
  • #1
Nervous
17
0
Does anyone know a good website or other source for practicing conversions and really just units in general? I'm having trouble with them, I'll give you an example problem I did to illustrate my problem...

What is the pressure at a depth of 5 meters in alcohol? (The specific gravity of alcohol is .8)

Pressure in water = weight density*depth
Sg=mass density/ mass density of water -> .8 = mass density/ 1 = .8g/ccm (cubic centimeter)
weight= mass*9.8 (force of gravity on Earth.) = .8*9.8=7.84 Newtons
depth= 5 meters
Pressure= 7.84N*5 meters = 39.2N/m

The book answers are

Mass density of Alcohol= 800 kilograms per cubit meter
Weight density of Alcohol= 7840 Newtons per cubic meter
Pressure at 5 meters deep in alcohol= 39,200 Newtons per square meter= 3.92 Netwons per square centimeter.

What was the correct way of doing that problem? I know I did the math right, it's the units that are troubling me.
 
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  • #3
What you did wrong is not convert properly between meters and centimeters. Keep the units as part of your computation, and you won't have these problems. Watch. I'm going to just multiply all the numbers together, as you did, but I'll keep units going all the way through.

(9.8 m/s²) * (0.8 g/cm³) * (5 m) = 39.2 m*g*m/(s²*cm³) = 39.2 g*m²/(cm³ * s²)

That's actually the correct answer, but the units of that answer are not pretty. So we look for things to simplify. First, you notice that you have meters at the top and centimeters at the bottom. You can do some cancellation using the fact that m/cm = 100.

39.2 g*m²/(cm³ * s²) = 39.2 * (m/cm) * g * m/(cm² * s²) = 39.2 * 100 * g * m/(cm² * s²) = 39.2 * 100 * 100 g/(cm*s²) = 392,000 g/(cm * s²).

That's better, but the units turned out to be CGS, and it'd be nicer to have the result in SI. Now, m/cm = 100 as we established, so 100cm / m = 1, and we can always multiply by 1. Let's do that.

392,000 g/(cm * s²) * 1 = 392,000 g/(cm * s²) * (100 cm/m) = 39,200,000 g/(m * s²)

Now we want to get rid of grams. 1kg / 1g = 1000, so 1 = 1kg/(1000 g)

39,200,000 g/(m * s²) * 1kg / (1000g) = 39,200 kg/(m * s²)

That's SI already. Final trick is to realize that what you are looking for is pressure, which is in N/m². Let's see if we can get it to that form. 1N = 1kg * m / s². Or 1 = 1N * s² / (kg * m). Let's multiply by 1 again.

39,200 kg/(m * s²) * (1N * s² / (kg * m)) = 39,200 N/m².

You can leave it like this, or convert this to Pa, using 1Pa = 1N/m², or to kPa, using 1kPa = 1000Pa. But you always do the same thing. You multiply and divide units as if they were variables expressed in terms of other units.

Once you have enough practice working with units, you won't need to carry out such long chains of computations. You'll be able to use many shortcuts. But while you are feeling uncertain, carry out each step explicitly to avoid making mistakes.
 

1. How do you convert units in physics?

To convert units in physics, you must use conversion factors. A conversion factor is a ratio of equivalent measurements. You can use this ratio to convert from one unit to another by multiplying the original quantity by the conversion factor.

2. What is the importance of unit conversions in physics?

Unit conversions are important in physics because they help us understand and compare different physical quantities. By converting units, we can easily express measurements in a more convenient or standardized form, making it easier to analyze and interpret data.

3. Can you convert between different systems of units?

Yes, it is possible to convert between different systems of units in physics. The most commonly used systems of units are the metric system and the imperial system. You can use conversion factors to convert between these systems or any other systems of units.

4. How do you convert from one prefix to another in the metric system?

To convert from one prefix to another in the metric system, you can use the fact that each prefix represents a multiple of 10. For example, to convert from centimeters to meters, you would divide the value in centimeters by 100, or move the decimal point two places to the left. To convert from meters to millimeters, you would multiply the value in meters by 1000, or move the decimal point three places to the right.

5. What are some common mistakes to avoid when doing unit conversions in physics?

Some common mistakes to avoid when doing unit conversions in physics include forgetting to include the correct conversion factor, using the wrong direction of conversion, and incorrectly cancelling units. It is important to double check your work and make sure your final answer has the correct units and significant figures.

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