- #1
bohemian
- 6
- 0
I need help finding the formula for the compound in this problem:
You have been given a bottle of hydrated oxalic acid (contains x number of water molecules) with a half-torn label, and have been asked to determine the exact formula of this compound. Your best guess on the formula of this molecule is [tex]H_{2}C_{2}O_{4} \bullet xH_{2}O[/tex]. To figure out the exact formula of this compund, you make a solution by taking 5.00g of this compound, dissolve it in exactly 250mL of water. You then remove 25.0mL of this solution and titrate it with 0.500 M sodium hydroxide. You find that the solution requires 15.9mL of the base for neutralization. Based on this experiment, determine the exact formula of the compound (you need to determine x).
If anyone can walk me through this and help me get the answer, I'd really appreciate it.
You have been given a bottle of hydrated oxalic acid (contains x number of water molecules) with a half-torn label, and have been asked to determine the exact formula of this compound. Your best guess on the formula of this molecule is [tex]H_{2}C_{2}O_{4} \bullet xH_{2}O[/tex]. To figure out the exact formula of this compund, you make a solution by taking 5.00g of this compound, dissolve it in exactly 250mL of water. You then remove 25.0mL of this solution and titrate it with 0.500 M sodium hydroxide. You find that the solution requires 15.9mL of the base for neutralization. Based on this experiment, determine the exact formula of the compound (you need to determine x).
If anyone can walk me through this and help me get the answer, I'd really appreciate it.