Compression spring constant k?

In summary, the formula for a compression spring's spring constant k depends on multiple factors including the material's shear modulus, the diameter of the wire, and the outer diameter and pitch angle of each winding. Some sources only consider the first three factors, while others also take into account the pitch angle or rise angle θ. However, the first type of treatment is incorrect as the pitch angle cannot be overlooked and greatly affects the stiffness of the spring. The formula also shows that for a fixed number of coils, the stiffness does not depend on the pitch angle, but rather on the length of the spring. As the pitch angle approaches 90 degrees, the stiffness increases significantly due to the decrease in the number of active coils.
  • #1
bobfei
30
0
Hi,

Compression_Springs.JPG

Does a compression spring’s pitch or rise angle have any relation with its spring constant k?
I checked various sources and they differ on this. Some sites simply asks you to feed input into a simple formula:
k=Gd4/3D3na
in which
k: spring constant
G: material’s shear modulus
d: diameter of the wire
D: outer diameter of each winding​
An example of this treatment can be found at http://www.efunda.com/DesignStandards/springs/calc_comp_designer_eqn.cfm.

On the other hand, some other sites require knowing the pitch between each winding, or equivalently rise angle θ, and result varies with different pitch/θ even all four parameters above remain unchanged. An example is at http://www.planetspring.com/pages/compression-spring-calculator-coil-calculator.php?id=compression.

I strongly suspect the first type of treatment above is incorrect. Consider extreme case:
1. θ →0° : This means we are not winding the spring up so all windings remains on the same plane. Of course when approaching this extreme k would approach zero.
2.. θ →90°: This corresponding the case when we are pulling the string straight without any winding and it points straight upward. Trying to compressing such a “spring” on the two ends is like compressing a stick rod, and we would get extremely large resistance due
to the rigidity of the material itself. Obviously in this case k → infinity​

It is then quite clear that θ cannot be overlooked, and the first kind of treatment above is obviously wrong.

I wonder why so many websites are still providing that answer? Could someone help or give a derivation of the compression spring k formula?


Bob
 

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  • #2
Your first formula includes ##n_a## which is thie number of active coils in the spring. If you change the pitch angle, then for a fixed length of spring you change ##n_a##.

Actually the first formula tells you something interesting: for a foxed number of coils, the stiffness does NOT depend on the pitch angle. A "long" spring with 10 coils and a big pitch angle has about the same stiffness as a "short" spring with 10 coils and a small pitch angle.

You can only choose two of the pitch angle, the length of the spring, and the number of coils as independent quantities.
 
  • #3
Aleph,
AlephZero said:
Actually the first formula tells you something interesting: for a foxed number of coils, the stiffness does NOT depend on the pitch angle. A "long" spring with 10 coils and a big pitch angle has about the same stiffness as a "short" spring with 10 coils and a small pitch angle.
This is what I cannot understand: why k(small angle, 10 coils) = k(large angle, 10 coils)? see the below extreme-case reasoning?
Bobsun said:
1. θ →0° : This means we are not winding the spring up so all windings remains on the same plane. Of course when approaching this extreme k would approach zero.
2.. θ →90°: This corresponding the case when we are pulling the string straight without any winding and it points straight upward. Trying to compressing such a “spring” on the two ends is like compressing a stick rod, and we would get extremely large resistance due
to the rigidity of the material itself. Obviously in this case k → infinity
 
  • #4
Why do you think k approaches 0 when the angle is small? Allowing for the fact that the coils can't intersect each other, when θ → 0 the wire is wound into a spiral. That acts like a curved beam, and its stiffness depends on the length of the wire (i.e. the number of turns).

For a fixed number of turns (and a fixed length of wire), it doesn't make much difference if the angle is exactly 0 or just close to 0.

These simple formulas don't really apply when θ → 90, but for a fixed length of spring, as θ → 90 the number of turns ##n_a## → 0 so the first formula does predict the stiffness gets very large.
 

1. What is a compression spring constant k?

A compression spring constant k, also known as the spring rate, is a value that represents the amount of force required to compress a spring by a certain distance. It is typically measured in units of force per distance, such as newtons per millimeter or pounds per inch.

2. How is the compression spring constant k calculated?

The compression spring constant k can be calculated by dividing the applied force by the distance the spring is compressed. This is known as Hooke's Law, which states that the force applied to a spring is directly proportional to the distance it is compressed.

3. What factors affect the value of the compression spring constant k?

The value of the compression spring constant k is affected by several factors, including the material of the spring, the diameter and length of the coils, and the number of coils. The type of end connections and the direction of the force applied can also impact the value of k.

4. How does the compression spring constant k impact the performance of a spring?

The compression spring constant k determines the stiffness of a spring, which affects its ability to resist external forces and return to its original shape after being compressed. A higher k value means the spring is stiffer and will require more force to compress, while a lower k value indicates a more flexible spring.

5. Can the compression spring constant k be changed?

Yes, the compression spring constant k can be changed by altering the design or material of the spring. For example, using a thicker wire or increasing the number of coils will result in a higher k value, while using a thinner wire or decreasing the number of coils will result in a lower k value. However, the k value is also affected by the physical properties of the material used, so changing the material may also impact the value of k.

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