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A house has a floor area of 200 m^2 and an outside wall that has an area of 50.0 m^2. The Earth's magnetic field here has a horizontal component of 2.58×10^-5 T that points due north and a vertical component of
4.14×10^-5 T that points straight down, toward the earth. a)Determine the magnetic flux through the wall if the wall faces north. b)calculate the flux that passes through the floor.
a)
flux=BAcos(theta)
=(4.14*10^-5)(50 m^2)(cos 90 deg)
=0 Wb
b)
flux=BAcos(theta)
=(2.58*10^-5)(200 m^2)(cos 0 deg)
=5.16*10^-3 Wb
I'm not sure what I did wrong.
4.14×10^-5 T that points straight down, toward the earth. a)Determine the magnetic flux through the wall if the wall faces north. b)calculate the flux that passes through the floor.
a)
flux=BAcos(theta)
=(4.14*10^-5)(50 m^2)(cos 90 deg)
=0 Wb
b)
flux=BAcos(theta)
=(2.58*10^-5)(200 m^2)(cos 0 deg)
=5.16*10^-3 Wb
I'm not sure what I did wrong.