- #1
mandy9008
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Homework Statement
A 580 N uniform rectangular sign 4.00 m wide and 3.00 m high is suspended from a horizontal, 6.00-m-long, uniform, 80-N rod as indicated in the figure below. The left end the rod is supported by a hinge and the right end is supported by a thin cable making a 30.0° angle with the vertical.
(a) Find the tension, T, in the cable.
(b) Find the horizontal and vertical components of force exerted on the left end of the rod by the hinge. (Take up and to the right to be the positive directions.)
The Attempt at a Solution
a. (580N + 80N)(3.0m) = T cos(30) (6.0m)
T= (660N)(3.0m)/(6.0m cos 30)
T=381.1N
b. Tv=T cos 30
Tv=381.1 N cos 30
Tv=330.0 N up
Fv= Tv-W
Fv= -(330.0 N - 660 N)
Fv=330 N up
Th=T sin 30
Th=381.1 N sin 30
Th= 190.6 N to left (-190.6N)
Fh=190.6 to the right