- #1
chazgurl4life
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A 4.6 kg block is pushed 5.6 m up a rough 37° inclined plane by a horizontal force of 75 N. If the initial speed of the block is 2.2 m/s up the plane and a constant kinetic friction force of 25 N opposes the motion, *calculate the following: A) the inital KE of the block
B) the work done by the 75N force
C) The work done by friction force
D) the work done bt gravity.
Now i figured out that a) initial KE = 1/2mv^2=.5(4.6kg)(cos37 degrees)
B) Work done by the 75N= Fdcostheta=75N(5.6m)(cose37)
Now c &d are presenting a problem for me
B) the work done by the 75N force
C) The work done by friction force
D) the work done bt gravity.
Now i figured out that a) initial KE = 1/2mv^2=.5(4.6kg)(cos37 degrees)
B) Work done by the 75N= Fdcostheta=75N(5.6m)(cose37)
Now c &d are presenting a problem for me