Doppler Effect and Relativity

In summary: The range of wavelengths that can be observed for an atom in a gas is given by Y = v/f where v is the speed of the atom and f is the frequency of the spectral line. The range of wavelengths can be expanded to include a wider range of wave-lengths by using the doppler equation which states that the wave-length difference between the waves observed when the atom is moving towards and away from the observer is given by Y = v/f_s.
  • #1
aznkid310
109
1

Homework Statement



Hydrogen's only visible spectral lines are 656, 486, 434, and 410 nm. If spectral lines were of absolutely precise wavelength, they would be very difficult to discern. Fortunately, two factors broaden them: the uncertainty principle and the doppler broadening.
Atoms in a gas are in motion, so some light will arrice that was emitted by the atoms moving toward the observer and some atoms moving away. Thus, the light reaching the observer will cover the range of wavelengths.

Making the assumption that atoms move no faster than their rms speed

v_r = sqrt[2kT/m], where k = boltzman constant

Obtain a formula for the range of wavelengths in terms of the wavelength Y of the spectral line, the atomic mass m, and the temperature T. (note v_r << c)


Homework Equations



I'm not sure how to solve for a whole range of wavelengths. I used the formula Y = v/f and plugged in the doppler formula, but I am stuck there.

The resulting answer should be { 2Y*sqrt[(3kT/m)] }/c

The Attempt at a Solution



Moving toward observer:

f_observed = (f_source)*sqrt[(1+v/c)/(1-v/c)]

Then Y = v/f_observed = (sqrt[2kT/m]) / ((f_source)*sqrt[(1+v/c)/(1-v/c)])
 
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  • #2
You are told that the molecular speeds are non-relativistic, so you can either use the non-relativistic form of the Doppler equations, or simply take the limit v<<c in the above expression.

Then the thing you want to do is find the spread in wave-lengths, which is the difference between the wave-lengths observed for the 2 cases: (i) moving towards, and (ii) moving away from the observer.
 
  • #3
Do you mean to take v -> 0 in the Y expression and then do it for moving toward the observer? Then take the difference?

If i to that, then Y = (sqrt[2kT/m])/f_s for both cases.
 
  • #4
aznkid310 said:
Do you mean to take v -> 0 in the Y expression and then do it for moving toward the observer? Then take the difference?
Not v-> 0, but v/c << 1. You need to Taylor expand the square root quantity and discard terms of second or higher order in v/c. What you get should be the same expression as the non-relativistic equation.
 

1. What is the Doppler effect?

The Doppler effect is a phenomenon that occurs when there is a perceived change in the frequency of a wave due to the relative motion between the source of the wave and the observer. This effect is commonly observed in sound waves, such as the change in pitch of an ambulance siren as it passes by.

2. How does the Doppler effect relate to relativity?

The Doppler effect plays a crucial role in the theory of relativity, as it is used to explain the observed redshift and blueshift of light from celestial objects. According to the theory of relativity, the relative motion between the source of light and the observer can cause a change in the frequency of light, which is perceived as a change in color.

3. How does the Doppler effect affect the measurement of distances in space?

The Doppler effect can affect the measurement of distances in space by causing a shift in the observed frequency of light from distant objects. This shift in frequency is used to calculate the radial velocity of these objects, which in turn is used to determine their distance from Earth.

4. Can the Doppler effect be observed in all types of waves?

Yes, the Doppler effect can be observed in all types of waves, including sound, light, and even water waves. However, the amount of frequency shift may differ depending on the type of wave and the relative velocity between the source and the observer.

5. How does the Doppler effect support the theory of relativity?

The Doppler effect provides evidence for the theory of relativity by showing that the perceived frequency of light can be affected by the relative motion between the source and the observer. This supports the idea that the laws of physics are the same for all observers, regardless of their relative motion.

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