Only quasistatic process can be a polytropic process

In summary, the conversation discusses the definitions of adiabatic and quasi-static processes and their relation to polytropic processes. It is stated that a process can be considered adiabatic if it occurs fast enough, but this also poses a threat to it being quasi-static. It is also mentioned that a gas can only be described by a single set of thermodynamic variables during a quasi-static process, and that this may not be the case during a fast adiabatic process. The example of the speed of sound being derived using an adiabatic process is given, but it is noted that this process may not be completely quasi-static.
  • #1
atavistic
106
0
We may say a process is adiabatic if it occurs fast enough such that no heat is exchanged from the system.But we also say a process is quasi-static when it occurs very slow.

Then how can PV^gamma = c hold for a fast occurring adiabatic process because a polytropic process should be quasistatic as wiki says http://en.wikipedia.org/wiki/Polytropic_process .

Also why is it true that only quasistatic process can be a polytropic process.?
 
Physics news on Phys.org
  • #2
atavistic said:
But we also say a process is quasi-static when it occurs very slow.

Says who? A process that occurs slowly may be quasistatic but that doesn't necessarily make it so. A quasistatic process is a process that occurs near thermodynamic equilibrium. How the term "near" is described in the last sentence is open to interpretation.

A quasistatic system is also a system that occurs over several of these near equilibrium states so that eventually the final state is different from the initial state, which can be considered of occurring slowly depending on the amount of the states you want to create for a given process.
 
  • #3
It is implicitely assumed that throughout the process the thermodynamic variables like tempersture and pressure are well defined, so it has to be a quasi-static process. If you let a gas expand faster and faster, then what will start to happen is that during the expansion process the gas cannot be described by a single set of thermodynamical variables. You'll get a shock wave that propagtes through the gas, so you need to describe the gas using a position dependent temperature, pressure, density, and flow velocity.

But this description is also just an approximation. If the expansion process is sufficiently violent, local thermodynamic equilibrium will also break down. In that case the velocity distribution of the molecules at any given point in the gas during the expansion process is can no longer be approximated by the Maxwell distribution.

Such a gas can only be described by a propabaility distribution over velocity and configuration space. The time evolution is given by the Boltzmann equation.
 
  • #4
So basically can I say even when a process occurs fast, it can be quasistatic if its state can be defined using gas laws. For e.g. the speed of sound has been derived using an adiabatic process , the reason being that the time difference is so small such that no heat is exchanged and then the relation PV^gamma is used. So it means that the state of the air is defined during compression and rarefaction even though these events occur very fast.
 
  • #5
atavistic said:
So basically can I say even when a process occurs fast, it can be quasistatic if its state can be defined using gas laws. For e.g. the speed of sound has been derived using an adiabatic process , the reason being that the time difference is so small such that no heat is exchanged and then the relation PV^gamma is used. So it means that the state of the air is defined during compression and rarefaction even though these events occur very fast.

Yes, but note that the speed of the process which makes the process adiabatic also threatens to make the process not quasistatic. In the case of a soundwave you mention, you have local thermodynamical equilibrium, i.e. at every point in the gas you have a well defined pressure, density and temperature, which evolves adiabatically to a good approximation. But obviously, global thermodynamical equilibrium has broken down: The entire gas cannot be described by a single pressure and temperature. If it could, there wouldn't be a sound wave.
 

What is a quasistatic process?

A quasistatic process is a process in which the system changes its state slowly enough that it can be considered in equilibrium at all times. This means that the system can be described by a series of equilibrium states, rather than constantly being in a state of change.

What is a polytropic process?

A polytropic process is a process in which the relationship between pressure and volume can be expressed as a power law equation, such as P∝V^γ. This means that the process can be described by a single polytropic index, γ.

Why can only quasistatic processes be polytropic?

This is because the polytropic equation only holds true for processes in which the system is in equilibrium at all times. Quasistatic processes are the only type of processes that meet this requirement, as they change slowly enough to always be in equilibrium.

What makes quasistatic processes different from other types of processes?

Quasistatic processes are distinguished by their slow and incremental changes, which allow for the system to remain in equilibrium at all times. This is in contrast to other types of processes, such as dynamic or irreversible processes, which involve rapid changes and do not maintain equilibrium.

Why is it important to consider quasistatic processes in scientific studies?

Quasistatic processes are important because they allow for the mathematical modeling and analysis of thermodynamic systems. This is because their slow and controlled nature makes them easier to study and understand, and the equilibrium states they pass through can be accurately described by equations and laws.

Similar threads

  • Advanced Physics Homework Help
Replies
5
Views
1K
Replies
4
Views
2K
Replies
8
Views
998
Replies
5
Views
2K
Replies
1
Views
645
Replies
2
Views
4K
Replies
6
Views
2K
Replies
4
Views
14K
  • Classical Physics
Replies
4
Views
3K
Back
Top