- #36
Mark44
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Let's stay focused here. How can you fix the equation you posted in post #15?
This is the part that's wrong:
(x-2)/( 1-(x +2)) = (x-2)/ (-x-1)
Jbreezy said:##\sum_{n = 1}^{\infty}(x + 2)^n = \sum_{n = 1}^{\infty}(x + 2)(x + 2)^{n-1} = (x-2)/( 1-(x +2)) = (x-2)/ (-x-1) ##
This is the part that's wrong:
(x-2)/( 1-(x +2)) = (x-2)/ (-x-1)