- #1
broegger
- 257
- 0
Hi,
I am told that [tex]\text{BaCO}_3_{(s)}[/tex] is sparingly soluble in water with a solubility product [tex]K_{sp} = 8.1\cdot10^{-9}~M^2[/tex]. I have to write the expression for the solubility product, but how do I know which ions Ba and CO3 forms (e.g. [tex]Ba^{+},~Ba^{2+},~Ba^{3+},\ldots[/tex]). I happen to know that the expression is
but how can you find out?
I am told that [tex]\text{BaCO}_3_{(s)}[/tex] is sparingly soluble in water with a solubility product [tex]K_{sp} = 8.1\cdot10^{-9}~M^2[/tex]. I have to write the expression for the solubility product, but how do I know which ions Ba and CO3 forms (e.g. [tex]Ba^{+},~Ba^{2+},~Ba^{3+},\ldots[/tex]). I happen to know that the expression is
[tex]K_{sp} = [Ba^{2+}][{CO_3}^{2-}],[/tex]
but how can you find out?