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leejqs
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Homework Statement
After falling from rest at a height of 29.8 m, a 0.422 kg ball rebounds upward, reaching a height of 21.7 m. If the contact between ball and ground lasted 1.83 ms, what average force was exerted on the ball?
Homework Equations
Change in momentum (p) = Fnet* Change in Time
FGrav=m*g
Delta y = Vavg,y*Change in Time
The Attempt at a Solution
I understand all of these formulas, but I am not quite sure where the 1.83 ms goes as far as which time it is actually describing in a specific formula. I know that the average velocity on the way down is actually just the final velocity divided by 2, since the initial velocity is 0... I feel like I'm on the brink of solving this but I'm not quite sure where to go next..
Thanks!