- #1
aisha
- 584
- 0
I have a question that says an equivalent expression for [tex]\cos\frac {3\theta} {2} \cos \frac {\theta} {2} + \sin \frac {3\theta} {2} \sin\frac {\theta} {2} [/tex] is??
How do u get the answer to be [tex] \cos \theta [/tex]?
Can someone please help me out?
How do u get the answer to be [tex] \cos \theta [/tex]?
Can someone please help me out?